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When \`a != 0\`, there are two solutions to \`ax^2 + bx + c = 0\`.
They are:
<p style="text-align:center">
`x = (-b +- sqrt(b^2-4ac))/(2a) .`
</p>
Output:
When `a != 0`, there are two solutions to `ax^2 + bx + c = 0`. They are:
`x = (-b +- sqrt(b^2-4ac))/(2a) .`