{"id":918,"date":"2015-01-17T15:31:19","date_gmt":"2015-01-17T21:31:19","guid":{"rendered":"http:\/\/www.ssc.wisc.edu\/~jfrees\/?page_id=918"},"modified":"2015-02-20T18:24:49","modified_gmt":"2015-02-21T00:24:49","slug":"policy-values-at-fractional-durations","status":"publish","type":"page","link":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/actuarial-mathematics\/policy-values\/8-policies-with-discrete-cash-flows-other-than-annual\/policy-values-at-fractional-durations\/","title":{"rendered":"Policy Values at Fractional Durations"},"content":{"rendered":"<p>An insurance company takes on contracts continuously throughout the year yet has a single valuation date (e.g., 1 July 20xx). Thus, even for traditional policies with annual cash flows, one needs the policy value when the duration includes a fraction of a year. Of course, for a fully continuous policy value, no special adjustments need be made.<\/p>\n<p>Let \\(k\\) denote the integer duration time and \\(s\\) denote the fractional time, so that \\(0< s< 1\\) and the duration time is \\(k+s\\). For a fully discrete policy, as we have seen, the policy value can be expressed recursively as\n\\begin{eqnarray*}\n_k V&#038;=&#038; v q_{x+k} b_{k+1} - P_k + v p_{x+k} ~_{k+1} V.\n\\end{eqnarray*}\nNow, for \\(0< s< 1\\), we define the policy value at fractional duration to be\n\\begin{eqnarray*}\n_{k+s} V &#038;=&#038; v^{1-s} ~_{1-s} q_{x+k+s} ~b_{k+1} + v^{1-s} ~_{1-s} p_{x+k+s} ~_{k+1} V .\n\\end{eqnarray*}\nTo evaluate this, under UDD we have\n\\begin{eqnarray*}\n~_{1-s} q_{x+k+s} &#038;=&#038; \\frac{(1-s) q_{x+k}}{1- s \\times q_{x+k}}\n\\end{eqnarray*}\nand\n\\begin{eqnarray*}\n~_{1-s} p_{x+k+s} &#038;=&#038; \\frac{p_{x+k}}{1- s \\times q_{x+k}} .\n\\end{eqnarray*}\nThus,\n\\begin{eqnarray*}\n_{k+s} V &#038;=&#038; \\frac{v^{1-s}}{1- s \\times q_{x+k}}\n\\left( (1-s) \\left\\{q_{x+k} b_{k+1}\\right\\} + p_{x+k} ~_{k+1} V \\right) \\\\\n&#038;=&#038; \\frac{v^{1-s}}{1- s \\times q_{x+k}}\n\\left( (1-s)\\left\\{ (P_k +V_k)(1+i) - p_{x+k} ~_{k+1} V\n\\right\\} + p_{x+k} ~_{k+1} V \\right) \\\\\n&#038;=&#038; \\frac{v^{1-s}}{1- s \\times q_{x+k}}\n\\left( (1-s) (1+i)(P_k +~_k V) +s \\times p_{x+k} ~_{k+1} V \\right) \\\\\n&#038;\\approx &#038;\n(1-s) (P_k +~_k V) +s \\times ~_{k+1} V.\n\\end{eqnarray*}\nThis approximation assumes a small mortality rate so that \\(q_{x+k} \\approx 0\\) and small interest rate so that \\(v^{-s} \\approx 1\\) and \\(v^{1-s} \\approx 1.\\)\n\nIt is common to write this approximation as\n\n\n<table align=\"center\" border=\"1\">\n<tbody>\n<tr>\n<td align=\"center\">\\(~_{k+s} V =\\)<\/td>\n<td align=\"center\">\\((1-s) ~_k V +s ~_{k+1} V\\)<\/td>\n<td align=\"center\">+\\((1-s) P_k\\)<\/td>\n<\/tr>\n<tr>\n<td align=\"center\"> <font size=\"4\">reserve<\/font><\/td>\n<td align=\"center\">    <font size=\"4\">interpolate terminal reserves   <br \/>\n\t\t\t<\/font><\/td>\n<td align=\"center\"> <font size=\"4\">unearned premiums<\/font><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>where \\(_k V, ~_{k+1} V\\) are known as &#8220;terminal reserves&#8221; and \\((1-s) P_k\\) is that portion of the annual premium that has been collected but &#8220;not earned&#8217; by the valuation date.<\/p>\n<p><strong>Example.<\/strong> (Act Mat, p. 219) Consider a 5-year term policy to (50) with \\(P = 1000 P_{50:\\overline{5|}}^{~1} = 6.55692\\), \\(V_2 = 1.64\\), and \\(V_3 = 1.73\\). Then, we may compute the policy value at duration \\(k+s=2.25\\) as<br \/>\n\\begin{eqnarray*}<br \/>\n~_{2+0.25} V &#038;\\approx &#038;<br \/>\n(1-0.25) (P_2 + ~_2 V) +0.25 \\times ~_3 V \\\\<br \/>\n&#038;=&#038; (1-0.25) (6.55692 +1.64) +0.25 \\times 1.73 = 6.58 .<br \/>\n\\end{eqnarray*}<\/p>\n<p><div class=\"alignleft\"><a href=\"https:\/\/users.ssc.wisc.edu\/~ewfrees\/actuarial-mathematics\/policy-values\/8-policies-with-discrete-cash-flows-other-than-annual\/special-case-2-whole-life-policy\/\" title=\"Special Case 2. Whole Life Policy\">&#9668 Previous page<\/a><\/div><div class=\"alignright\"><a href=\"https:\/\/users.ssc.wisc.edu\/~ewfrees\/actuarial-mathematics\/multiple-decrement-models\/\" title=\"Multiple Decrement Models\">Next page &#9658<\/a><\/div><\/p>\n","protected":false},"excerpt":{"rendered":"<p>An insurance company takes on contracts continuously throughout the year yet has a single valuation date (e.g., 1 July 20xx). Thus, even for traditional policies with annual cash flows, one needs the policy value when &hellip;<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":911,"menu_order":2,"comment_status":"closed","ping_status":"open","template":"","meta":{"jetpack_post_was_ever_published":false},"jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/P8cLPd-eO","acf":[],"_links":{"self":[{"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/pages\/918"}],"collection":[{"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/comments?post=918"}],"version-history":[{"count":5,"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/pages\/918\/revisions"}],"predecessor-version":[{"id":1592,"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/pages\/918\/revisions\/1592"}],"up":[{"embeddable":true,"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/pages\/911"}],"wp:attachment":[{"href":"https:\/\/users.ssc.wisc.edu\/~ewfrees\/wp-json\/wp\/v2\/media?parent=918"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}